Question

For which value of k the quadratic equation kx2-3x+k=0 has real and equal roots​

Answer 1

Step-by-step explanation:

Here, we have kx

2

+1=kx+3×−11k

2

(k+11)x

2

−(k+3)x+1=0

a=k+11

⇒b=−(k+3)=c=1

Since, given equation has real & equal roots, so D = 0

b

2

−4ac=0

(−k−3)

2

−4(k+11)(1)=0

k

2

+2k−35=0

⇒(k+7)(k−5)=0

k=−7,5.