for which value of p does the pair of equation gives below has unique solution 4x+py+8=0and 2x+2y+2=0
Answers
Answered by
5
For a unique solution, it satisfies intersecting line.
a1/a2≠b1/b2
4x+py+8=0 and 2x+2y+2=0
4/2≠p/2
4≠p
p≠4
Therefore p has all the values except 4.
a1/a2≠b1/b2
4x+py+8=0 and 2x+2y+2=0
4/2≠p/2
4≠p
p≠4
Therefore p has all the values except 4.
Similar questions