For which value of p will the equation (p^2 - 1) x^2 + px + q=0 not be a quadratic equation
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Solution:
_____________________________________________________________
Given & To Find:
The value of p, to the equation, not to become a quadratic equation,
(p²- 1)x² + px + q = 0,
_____________________________________________________________
We know that,
Quadratic equations are on the form ,
=> ax² + bx + c = 0,
where, a ≠0,/
For the given equation, to be a quadratic equation,
p² - 1 ≠ 0,
Hence,
=> p² - 1 = 0,
=> p² = 1
=> p = 1,..
∴ If p = 1, the equation becomes,
0x² + bx + 1 =0,
=> bx + 1 =0 (which is not a quadratic equation),
_____________________________________________________________
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_____________________________________________________________
Given & To Find:
The value of p, to the equation, not to become a quadratic equation,
(p²- 1)x² + px + q = 0,
_____________________________________________________________
We know that,
Quadratic equations are on the form ,
=> ax² + bx + c = 0,
where, a ≠0,/
For the given equation, to be a quadratic equation,
p² - 1 ≠ 0,
Hence,
=> p² - 1 = 0,
=> p² = 1
=> p = 1,..
∴ If p = 1, the equation becomes,
0x² + bx + 1 =0,
=> bx + 1 =0 (which is not a quadratic equation),
_____________________________________________________________
Helps of Helps!!
=> Mark as Brainliest<>!!
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