Question

For which values of K (1,1), Kx+2y-2=0 will be a solution of the equation

Answer 1

Answer:

K = 0

Step-by-step explanation:

=> Kx+2y-2

x = 1, and y =1

=> K*1+2*1-2

=> K + 2 -2

=> K

But, Given that

K = 0