Question

For which values of k does the pair of equations given below has unique solution? Kx+4y+5=0. 3x+2y+1=0

Answer 1

Kx+4y +5=0

3x+2y+1=0

For unique solution

A1/A2 should be not equal to B1/B2

Now k/3 should not be equal to 4/2

K/3 should not be equal to 2

K should not be equal to 6:

Step-by-step explanation:

Answer 2

Answer:

Given equation:-

4x+py+8=0

a  

1

​  

=4,b  

1

​  

=p,c  

1

​  

=8

2x+2y+2=0

a  

2

​  

=2,b  

2

​  

=2,c  

2

​  

=2

Since the given pair of equation hs unique solution.

Therefore,

a  

2

​  

 

a  

1

​  

 

​  

 



=  

b  

2

​  

 

b  

1

​  

 

​  

 

2

4

​  

 



=  

2

p

​  

 

⇒p



=4

Hence the given pair of equation has unique solution for all values of p except 4.