Math, asked by palisocaj870, 6 months ago

For which values of k is the set of order pairs (2,4), (k,6), (4,0) a function?​

Answers

Answered by keerthijaya7777
34

Step-by-step explanation:

A function means that every x goes to a different y, so any value for k other than 1,2, or 3 makes this a function.

For example, (2,8) would not work because you already have (2,6).

Note: (1,5) and (3,5) still work because they are DIFFERENT x's going to the same y.

Answered by Anonymous
0

The values of k are 1, 3, 5, 6, 7, 8, 9, and 0.

Given:

Ordered pairs: (2,4), (k,6), (4,0)

To find:

The values of k

Solution:

We know that the ordered pairs have to form a function.

So, in a pair (x, y), there can only be one value of y for x.

In the pairs (2, 4) and (4, 0), the value of y for 2 and 4 is 4 and 0, respectively.

Now, we know that in (k, 6), the values of k cannot be 2 or 4.

So, the possible values of k are 0, 1, 3, 5, 6, 7, 8, and 9.

Therefore, the values of k are 1, 3, 5, 6, 7, 8, 9, and 0.

#SPJ3

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