For x∈R, f(x) = |log2 – sinx| and g(x) = f(f(x)), then:
(1) g is differentiable at x = 0 and g'(0) =
-sin(log2)
(2) g is not differentiable at x = 0
(3) g'(0) = cos(log2)
(4) g'(0) = –cos(log2)
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Explanation:
for x ER,f (x)=log2-sinx and g (x)=f (f (x)),then:
g'(0)=-cos (log2)
SohomMondal:
Kindly explain by showing steps
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Explanation:
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