Question

force acts 0.1s on a body of mass 2 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2m/s.Find the magnitude of the force. *

20 N
45N
30 N
40N​

Answer 1

$\sf\red{\underbrace{Answer \implies 40\:N}}$

$\sf{\underline{\underline{Given:}}}$

$\sf{Mass\:(m) = 2\:kg}$

$\sf{Initial\:Velocity,\:(u) = 0}$

$\sf{Final\:Velocity,\:(v) = 2\:m{s}^{-1}}$

$\sf{ Time,\:(t) = 0.1\:s}$

$\sf{\underline{\underline{We\:Know\:That:}}}$

$\sf\orange{Acceleration = \dfrac{Change\:in\:Velocity}{Time}}$

$\sf\purple{\implies a= \dfrac{(v - u)}{t}}$

$\sf\green{\implies a = \dfrac{(2 - 0)}{0.1} = 20\:m{s}^{-1}}$

$\sf{\underline{\underline{Therefore:}}}$

$\sf\orange{ Force = Mass \times Acceleration}$

$\sf\green{\implies Force = (2) \times (20) = 40\:N}$