Question

force between 2 charges is f .now if distance is doubled what would happen to force
PLZ HELP​

Answer 1

Answer:

1/4th of initial

Explanation:

Force between two charges is inversely proportional to square of separation between them. If separation is doubled then force will decrease to 1/4th of its initial.

Answer 2

Answer:

1/4 of the previous one

Explanation:

Force is directly proportional to the product of charges and, inversely proportional to square of distance between them.

 F ∝ (q₀q₁)/r²

   When distance is twice of original, new distance is 2r.

Now,

 F ∝ (q₀q₁)/(2r)²

       ⇒ q₀q₁/4r²

       ⇒ (1/4) q₀q₁/r²

       ⇒ (1/4) F

It is 1/4 of the original