Question

force between two point charges kept at distance d appart in air is f. if the charges are kept at the same distance in water how does electric force between them change

Answer 1

force would be divided by the dielectric constant of water.

I don't remember the constant , might be given im question.

you can you solve from there

Answer 2

Answer:

$\frac{F}{80}$

Explanation:

Given :

`Force between two point charges kept at distance d apart in air is f.

if the charges are kept at the same distance in water how does electric force between them change,.

Solution :

We kn that,

Force between two charged particles in free space (air) is given by,

⇒ $\frac{Kq_1q_2}{d^2}$

⇒ where value of k changs from medium to medium, (k is permitivity of the medium )

For free space k =  1,

⇒ In air ,

Force (F) = $\frac{q_1q_2}{d^2}$  (as k ≈ 1),.

Hence,

In water it is 80 ,.

Hence force (F) = $\frac{F}{80}$

∴ The force in water reduces by the factor 1/80,.