Question

state and explain Graham's law of diffusion of gases?​

Answer 1

Answer:

$\underline{explanation}$

Graham's law of effusion was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. This formula can be written as: , where: Rate₁ is the rate of effusion for the first gas.

$\underline{formula}$

r_1 = rate of effusion for gas 1

r_2 = rate of effusion for gas 2

M_1 = molar mass of gas 1

M_2 = molar mass of gas 2

Answer 2

Answer:

Graham's law of effusion was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. This formula can be written as: , where: Rate₁ is the rate of effusion for the first gas.

\underline{formula}formula

r_1 = rate of effusion for gas 1

r_2 = rate of effusion for gas 2

M_1 = molar mass of gas 1

M_2 = molar mass of gas