. Force necessary to pull a circular plate of 5
cm radius from water surface for which
surface tension is 75 dynes/cm, is
A) 30 dyne B) 750 dynes
C) 60 dynes D) 750 dynes
and explain
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Step-by-step explanation:
Given Force necessary to pull a circular plate of 5 cm radius from water surface for which surface tension is 75 dynes/cm, is
- We have a circular plate of 5 cm radius.
- The total length of circular plate on which the force will act will be 2πr
- So force necessary to pull will be T x 2πR (circumference of circle)
- = 75 x 2π x 5
- = 750 π dynes
- = 2355 dynes.
- 1 dyne = 10^-5 N
- 2355 dyne = 2355 x 10^-5 N
750 π dynes is the force required to pull the circular plate.
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