Math, asked by madhuanchula001, 1 year ago

. Force necessary to pull a circular plate of 5
cm radius from water surface for which
surface tension is 75 dynes/cm, is
A) 30 dyne B) 750 dynes
C) 60 dynes D) 750 dynes
and explain​

Answers

Answered by knjroopa
6

Step-by-step explanation:

Given Force necessary to pull a circular plate of 5  cm radius from water surface for which  surface tension is 75 dynes/cm, is

  • We have a circular plate of 5 cm radius.
  • The total length of circular plate on which the force will act will be 2πr
  • So force necessary to pull will be T x 2πR (circumference of circle)
  •                                                       = 75 x 2π x 5
  •                                                          = 750 π  dynes
  •                                                         = 2355 dynes.
  •                                                      1 dyne = 10^-5 N
  •                                                     2355 dyne = 2355 x 10^-5 N

750  π  dynes is the force required to pull the circular plate.

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