Question

Force of 1:25 n acts on an object at rest after travelling a distance of 8 metre the speed of object in 10 M/S the mass of the object is as :
A) 1.25 kg
B) 2.5 kg
C )5 kg
D) 10kg
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:

Answer 1

$\huge \cal \underline \color{red}★A᭄ɴsᴡΣʀ࿐$

☆Given Information,

• ☘Force Applied (F) = 125 N
• ☘Initial Velocity (u) = 0 m/s
• ☘Final Velocity (v) = 10 m/s
• ☘Displacement (s) = 8m
• ☘From Work Energy Theorem,

★Net Work Done = Change in Kinetic Energy

☞Here, initial KE is in consiquential as the object was at rest initially.

»» F × s = 1/2mv²

»»125 × 8 × 2 = 100m

»» 100m = 250 × 8

»»100m = 2000

»» m = 20Kg

• ☛Mass of the object is 20Kg.

_________❤️__________

Answer 2

※Given Information,

※Given Information,Force Applied (F) = 125 N

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/s

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/s

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8m

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8mFrom Work Energy Theorem,

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8mFrom Work Energy Theorem,※Net Work Done = Change in Kinetic Energy

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8mFrom Work Energy Theorem,※Net Work Done = Change in Kinetic EnergyHere, initial KE is inconsiquential as the object was at rest initially.

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8mFrom Work Energy Theorem,※Net Work Done = Change in Kinetic EnergyHere, initial KE is inconsiquential as the object was at rest initially.F × s = 1/2mv²

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8mFrom Work Energy Theorem,※Net Work Done = Change in Kinetic EnergyHere, initial KE is inconsiquential as the object was at rest initially.F × s = 1/2mv²125 × 8 × 2 = 100m

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8mFrom Work Energy Theorem,※Net Work Done = Change in Kinetic EnergyHere, initial KE is inconsiquential as the object was at rest initially.F × s = 1/2mv²125 × 8 × 2 = 100m100m = 250 × 8

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8mFrom Work Energy Theorem,※Net Work Done = Change in Kinetic EnergyHere, initial KE is inconsiquential as the object was at rest initially.F × s = 1/2mv²125 × 8 × 2 = 100m100m = 250 × 8100m = 2000

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8mFrom Work Energy Theorem,※Net Work Done = Change in Kinetic EnergyHere, initial KE is inconsiquential as the object was at rest initially.F × s = 1/2mv²125 × 8 × 2 = 100m100m = 250 × 8100m = 2000m = 20Kg

※Given Information,Force Applied (F) = 125 NInitial Velocity (u) = 0 m/sFinal Velocity (v) = 10 m/sDisplacement (s) = 8mFrom Work Energy Theorem,※Net Work Done = Change in Kinetic EnergyHere, initial KE is inconsiquential as the object was at rest initially.F × s = 1/2mv²125 × 8 × 2 = 100m100m = 250 × 8100m = 2000m = 20Kg※Mass of the object is 20Kg.