Force of 10 N is acting on a body of mass 1 kg. If it covers a distance of 0.001 km in 4 seconds moving along a straight line, find its initial velocity.
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Hi,
Here is your answer
Given:
Force(F)=10N
Mass(m)=1kg
Distance(s)=0.001km=1m
Time taken(t)=4s
To find:
Initial velocity(u)
Solution:
We know that
Force=Mass×Acceleration
Hence
Acceleration=Force/Mass
Substituting the given datas
We get,
Acceleration=10/1=10m/s²
By second equation of motion
s=ut+1/2×a×t²
Substituting the datas
We get,
1=u×4+1/2×10×4²
u= -19.75m/s
The negative direction indicates that the direction of initial velocity is in the direction opposite to that of force applied.
Notes:
The three equations of motion are
- v=u+at
- s=ut+1/2×a×t²
- v²-u=2as
Hope this helps you.
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