Force of 72 dyne is inclined to the horizontal at 60°. Find acceleration in mass of 9g.
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Answer...
ATQ ,
m = 9g
F = 72 dyne
θ = 60°
Horizontal component of force ,
F' = F cos θ = 72 x ½
F' = 36 dyne
Acceleration ,
a = F'/m = 36/9
a = 4 cm/s²
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Hey !!
Horizontal component will be ,
72 cos 60 = 72 x ½
F = 36 dyne
a = F/m
a = 36 / 9
a = 4 cm/s²
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