Question

Force of athaction betereen two point
changes placed at distance d is f
What
distance apart should they be kept
in the same medium of that force between them is f/s​

Answer 1

Explanation:

Let us consider two point charges q1 and q2, placed at a distance d.

Force of attraction,

F = k (q1q2)/d²________(1)

Now, if the force becomes F/3, then let the distance between the point charges be r

Now, force of attraction,

F' = F/3 = k (q1q2)/r²______(2)

dividing equation, (1) and (2),we get

3 = r²/d²

⇒r² = 3 d²

⇒r = d√3

If the distance between them is d√3, the force will be F/3.

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