Physics, asked by a3lf8iybinDekjo, 1 year ago

FORCE OF ATTRACTION BETWEEN TWO POINT CHARGES PLACED AT A DISTANCE D APART IN A MEDIUM F. WHAT SHOULD BE THE DISTANCE IN THE SAME MEDIUM SO THAT THE FORCE BETWEEN THEM BECOMES 9F?

Answers

Answered by reck2
2
As F = kq1q2/r^2
where distance is r
So for force F to become 9F consider..
9F = kq1q2/r^2
or F = kq1q2/9r^2
so clearly distance should be 3r
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