force on a 1 kg on earth of radius R is 10N then the force on satellite revolving around the earth in the mean orbital radius 3R/2 will be
Answers
Answered by
5
F=mg.
g at a distance H from the surface of earth,
g'=gR^2/(R+H)^2
Here,
mg=10, m=1
Hence,g=10
mg'=1×10×R^2/(3R÷2)^2
(Mean orbital radius means R+H)
=40/9 N
Hope it will help u
g at a distance H from the surface of earth,
g'=gR^2/(R+H)^2
Here,
mg=10, m=1
Hence,g=10
mg'=1×10×R^2/(3R÷2)^2
(Mean orbital radius means R+H)
=40/9 N
Hope it will help u
Similar questions