Question

Force on a particle of mass 200g .velocity of the particle changes from 15ms-1 from 25ms-1 in 2.5s .assuming the force to be constant the magnitude of first is

Answer 1

$\\ m = 0.2 Kg \\ u = 15m/s \\ v = 25m/s \\ t = 2.5s \\ \\ v = u + at \\ \\ 25 = 15 + 2.5a \\ \\ 10 = 2.5a \\ \\ a = \frac {10}{2.5} = 4m/{s}^{2} \\ \\ F = m \times a \\ \\ F = 0.2 × 4 \\ \\ F = 0.8 N$

Answer 2

Given,

=> Mass = 200 g = 200/1000 Kg = 0.2 Kg

=> Initial Velocity = 15 m/s

=> Final Velocity = 25 m/s

=> Time = 2.5s

Now,

=> a = v-u/t

=> a = 25-15/2.5

=> a = 10/2.5 m/s^2

=> a = 4 m/s^2

Again,

As we know Force is equal to the product of Mass and Acceleration.

=> Force = mass x Acceleration

=> F = (0.2 x 4)Kg m/s^2

=> F = 0.8 N


Be Brainly