Physics, asked by harshmata3oybvei, 1 year ago

Force P, 2P and 3P are acting along three sides of an equilateral triangle ABC in cyclic order. Find the magnitude and direction of resultant.

Please solve this correctly and with step by step solution.

If you solve it on a page and then answer in the form of pic that would be better.

THANKS IN ADVANCE.

CORRECT ANSWER WILL BE MARKED BRAINLIEST.

Attachments:

Rajdeep11111: Is the answer zero?

harshmata3oybvei: no answer is √3P at angle of 30° with 3P

kushdubey1111: You are in which batch

kushdubey1111: I too am in IIT HOME

kushdubey1111: This is the physics assignment VPRA-V-23 right

kushdubey1111: I'll tell YSN/KLT/NHS

ArushiBhagat: I'm also in iit home

harshmata3oybvei: You are in which batch

harshmata3oybvei: By the way when answers were not displayed I wanted yo confirm all answers so I asked

Answers

Answered by Answers4u

For an equilateral triangle, all angles are equal A=B=C=60 degree

Sum of forces acting in HORIZONTAL direction:

F1 = P + 2P (-cos60) + 3P (-cos60)

= P + 2P (-1/2) + 3P (-1/2)

= -1.5P

Sum of forces acting in VERTICAL direction:

F2 = 0 + 2P (Sin60) + 3P (-sin60)

= 2P (0.866) + 3P (-0.866)

= -0.866P

Magnitude of resultant force (R)= Square root (F1 + F2)

= square root ((-1.5)^2 + (-0.866)^2))

= square root (3)

Magnitude R = 1.732P

Let ϴ be the angle of the resultant force in direction x

Then ϴ = tan-1 [(-1.5P)/(-0.866P)]

Direction of resultant force:

ϴ = 60 degree

harshmata3oybvei: Wrong answer!! then also Marking you brainliest bcoz your answer Was not been removed by mods

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