forces 10N, 20N ,30N and 40N acts along a side of the rectangle PQ QR RS ST their resultant force will be
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Their resultant force will be 2√20 N.
The rectangle is PQRS.
Given,
The forces are acting along the sides of the rectangle.
PQ = 10 N
QR = 20 N
RS = 30 N
ST = 40 N
Now, the forces along the sets (PQ, RS) and (QR, ST) act in anti-parallel.
So, the resultant of PQ and RS = (10-30) N
= -20 N
The resultant of QR and ST is = (20-40) N
= -20 N
They act at an angle of 90° with each other.
∴ The resultant of all the forces is, R = √{(-20)² + (-20)²}
∴ R = 2√20 N
The resultant of the forces is 2√20 N.
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