Question

forces 10N, 20N ,30N and 40N acts along a side of the rectangle PQ QR RS ST their resultant force will be​

Answer 1

Answer:

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Answer 2

Their resultant force will be 2√20 N.

The rectangle is PQRS.

Given,

The forces are acting along the sides of the rectangle.

PQ = 10 N

QR = 20 N

RS = 30 N

ST = 40 N

Now, the forces along the sets (PQ, RS) and (QR, ST) act in anti-parallel.

So, the resultant of PQ and RS = (10-30) N

                                                   = -20 N

The resultant of QR and ST is = (20-40) N

                                                 = -20 N

They act at an angle of 90° with each other.

∴ The resultant of all the forces is, R = √{(-20)² + (-20)²}

∴ R = 2√20 N

The resultant of the forces is 2√20 N.