Question

FORCES 2 N and FN act at 45° with one another to give a resultant √10 N . Then F =​

Answer 1

AB= Ladder = c=25 m

AC= Distance from the foot of the tower= b= 7 m

BC= Distance at which the ladder touches the wall. a= ?

So a^2 = c^2 -b^2

= a= √(25^2–7^2)

= √(625–49)

=√576= 24.

So the ladder touches vertical towel at a distance of 24- metres. When it slides 4- metres, then

a=20

c= 25

b=?

So b= (25^2–20^2)^0.5= 225^0.5 = 15.

Therefore when the ladder slides 4- metres from the tower, the distance from the foot of the ladder will he 15 metres from the ground.

So the ladder will slide a distance of (15–7)= 8- metres.