Math, asked by rutvik91, 5 months ago

Forces 3i-j+2k and i+3j-k acts on a particle and the particle goes from 2i+3j+k to 5i+2j+k under this forces; find the work done by the forces.

Answers

Answered by mehmoodasyeda16

2

Answer:

F=3i-j+2k+(i+3j-k)

F= 4i+2j+k

d=d2-d1

d=5i+2j+k-(2i+3j+k)

d= 3i-j+0

W=F×d

W=4i+2j+k×3i-j

W= 12(i)²-2(j)²

W=12-2

W= 10

rutvik91: Is it necessary to write joule next to answer as S.I. unit of work is joule? Is it necessary to write?

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