Question

Forces between two charges when placed in air is 4N. If they are placed in same distance apart in a medium of relative permiturty 2. Then the force between them will be.​

Answer 1

Answer: 2N

Explanation: Since relative permittivity is the ratio of forces between two charges when placed in air to the force b/w the charges when placed in any medium at same distance .

Now since

K=F(in air)/F(in medium).

(K= relative permittivity)

So, F(medium)=F(in air)/K

Hence, F(medium)=4/2=2N

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