Forces proportional to AB, BC and 2CA act along the sides of triangle ABC is order, their resultants represented in magnitude and direction is?
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Answered by
18
The force on side AB = AB
Force on BC = BC
Force on AC = 2CA
1.) Magnitude of AB = AC + CB
= 2CA - BC
2.) magnitude of BC = BA + AC
= 2CA - AB
3.) magnitude of AC = AB + BC
= AB + BC
Force on BC = BC
Force on AC = 2CA
1.) Magnitude of AB = AC + CB
= 2CA - BC
2.) magnitude of BC = BA + AC
= 2CA - AB
3.) magnitude of AC = AB + BC
= AB + BC
Answered by
9
Answer:
The force on side AB = AB
Force on BC = BC
Force on AC = 2CA
1.) Magnitude of AB = AC + CB
= 2CA - BC
2.) magnitude of BC = BA + AC
= 2CA - AB
3.) magnitude of AC = AB + BC
= AB + BCxplanation:
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