Math, asked by mahiraja05, 11 months ago

Form a cubic polynomial whose zeros are 3 ,2 and -1 hence

(i) find sum of its zero
(ii) sum of the product taken two at a time
(iii)product of its zero

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Answers

Answered by siddhartharao77
147

Answer:

x³ - 4x² + x + 6

Step-by-step explanation:

Let the zeroes be α,β,γ.

Given Zeroes are 3,2,-1.

(i) Sum of its Zeroes:

⇒ α + β + γ = 3 + 2 - 1

                   = 4.


(ii) Sum of the product taken two at a time:

⇒ αβ + βγ + γα = 3 * 2 + 2 * -1 + 3 * -1

                         = 1


(iii) Product of its zeroes:

⇒ αβγ = 3 * 2 * -1

           = -6.


Therefore, the cubic polynomial can be:

= x³ - (Sum of its zeroes)x² + (Sum of product taken two at a time)x - (Product of its zero)

= x³ - (α + β + γ)x² + (αβ + βγ + γα)x - (αβγ)

= x³ - 4x² + x + 6.


Therefore, the cubic polynomial is x³ - 4x² + x + 6.


Hope it helps!


mahiraja05: THANK YOU ❤️
siddhartharao77: Welcome!
Answered by Siddharta7
42

Let the cubic polynomial be p(x)


It's zeros are 3,2,-1


So the factors will be (x-3),(x-2),(x+1)


A cubic polynomial will at most have three zeros


So by multiplying all its three factors, we will get the polynomial


(x-3)(x-2)(x+1)


=(x²-2x-3x+6)(x+1)


=(x²-5x+6)(x+1)


=x³+x²-5x²-5x+6x+6


=x³-4x²+x+6


mahiraja05: THANK YOU ❤️
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