Question

form a quadratic equation whose roots are 3,4

Answer 1

Answer:

x^2-7x+12

Step-by-step explanation:

Let alpha be 3 and Beta be 4

Alpha +Beta =3+4=7

Alpha×Beta=3×4=12

The required Quadratic Equation is

x^2-alpha+Beta.x+alpha.beta=0

x^2-7x+12=0

Answer 2

The required quadratic equation is x² - 7x + 12 = 0, whose roots are 3 and 4.

Tips:

If a and b be the roots of a quadratic equation, then the quadratic equation is given by

(x - a) (x - b) = 0

Step-by-step explanation:

Given, the roots of the quadratic equation are 3 and 4.

So, the required quadratic equation is

(x - 3) (x - 4) = 0

⇒ x² - 4x - 3x + 12 = 0

⇒ x² - 7x + 12 = 0

∴ the required quadratic equation is x² - 7x + 12 = 0.

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