Question

Form a quadratic equation whose sum is 108 and the product of zero is -56

Answer 1

Step-by-step explanation:

The quadratic polynomial is bold{x^{2}-42 x-855=0}boldx

2

−42x−855=0

Step-by-step explanation:

Let the zeroes of the polynomial be represented as a and b.

Given one of the zeroes (a) = -15

Sum of the zeroes (a + b) = 42

a + b = 42 (i.e) -15 + b = 42

b = 42 - (-15)

b = 57

Product of the zeroes = a x b = -15 x 57 = -855

Hence the quadratic equation is x^{2}x

2

-(sum of the roots) x + Product of the roots = 0

x^{2}-42 x-855=0x

2

−42x−855=0

Answer 2

Answer:

it's alpha + beta = 108 and alpha× beta= -56.

now, formation of quadratic polynomial,

x^2-(alpha+ beta)x+(alpha×beta)=0

x^2-108x -56.

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