Question

Form a Quadratic polynomial whose one zero is 7-√3 and the sum of the zeroes is 14.​

Answer 1

Answer:

x^2 - 14x + 46

Step-by-step explanation:

Let the one zero be alpha : 7- root3

Then the another root will be beta

alpha + beta = 14

7 -root3 + beta = 14

beta = 7 + root3

alpha*beta = 7 - root3 * 7 + root3 =  46

GENERAL EQUATION : x^2 - ( alpha + beta )x + alpha * beta

therefore the equation will be x^2 - 14x + 46