Math, asked by harsh3456, 11 months ago

Form a quadratic polynomial, whose one zero is 8 and the product of zeroes is -56

Answers

Answered by tellmeplzz
1

Step-by-step explanation:

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Answered by windyyork
2

Answer: The required quadratic polynomial is x^2+x-56=0

Step-by-step explanation:

Since we have given that

One zero = 8

product of zeroes = -56

Let α and β are the two zeroes of the quadratic equation.

So, product of zeroes is represented as

\alpha\beta=-56\\\\8\beta =-56\\\\\beta=\dfrac{-56}{8}=-7

so, the quadratic equation would be

x^2-(\alpha +\beta )x-\alpha \beta =0\\\\x^2-(8-7)x+(-56)=0\\\\x^2+x-56=0

Hence, the required quadratic polynomial is x^2+x-56=0

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