Question

form a quadratic polynomial whose one zero is 8 and the product of the zeroes is-56

Answer 1

Given that the product of the zeros is -56 and one of the zero is 8

⇒ the other zero must be (-56 ÷ 8) = -7

Form the equation:

(x + 7) (x -8) = 0

Expand the expression:

x² - 8x + 7x - 56 = 0

Combine like terms:

x² - x - 56 = 0

Answer: The quadratic equation is x² - x - 56 = 0

Answer 2

here is your answer OK dude.............


☺☺☺☺☺☺☺

OK..................


Let the zeros of the quadratic equation be alpha and beta.

As given one zero of the quadratic Polynomial is 8, Hence Alpha = 8

Also Product of the zeroes = -56

Hence , Alpha * Beta = -56

= 8 * Beta = -56

= Beta = -56 / 8 = -7

As we know the product of the zeroes of a quadratic equation is equal to c/a and sum is equal to -b/a.

Therefore, Alpha * Beta = -56/1 = c/a

Also Alpha + Beta = 8 + (-7) = 1 / 1 = -b/a

Hence c = -56 and a = 1 and b = -1 from the above.

Therefore the equation would be :-

x2 - x - 56 = 0

OK it's help you.......