Question

Form+a+quadratic+polynomial+whose+zeroes+are+2/3+and+-1/3

Answer 1

Answer:

Given,

Zeroes = ( 2/3 ) and ( -1/4 )

We know the formula for a quadratic equation :

⇒ x² - ( Sum of zeroes )x + Product of zeroes = 0

Now , we have to find the sum of zeroes and product of zeroes .

Here we go,

⇒ Sum of zeroes = ( 2/3 ) + ( -1/4 )

= ( 2/3 ) - ( 1/4 )

= ( 8 - 3 ) / 12

= 5/12

And,

⇒ Product of zeroes = ( 2/3 ) ( -1/4 )

= ( -1/6 )

Now , plug these values in the above used formula.

⇒ x² - ( 5/12 )x + ( -1/6 ) = 0

⇒ ( 12x² - 5x - 2 ) / 12 = 0

⇒ 12x² - 5x - 2 = 0 × 12

⇒ 12x² - 5x - 2 = 0

Hence,

The required Quadratic Equation is :

⇒ 12x² - 5x - 2 = 0

hope it helped you