Form a quadratic polynomial whose zeroes are 2 5 and sum of zeroes is 4
Answers
Answer:
Given :Sum of the zeroes 4
one of the zero is 2+√5==α
another zero is 2-√5==β because 2+√5+β=4
β=4-2+√5
β=2-√5
So here in order to get the equation we need substitute in general formula of quadratic equation
x²-(α+β)+αb
x²-(4)x+(2+√5.2-√5) {(a+b)(a-b)==a²-b²}
x²-4x+(4-5)
x²-4x+(-1)
x²-4x-1 is the answer
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Answer:
Given :Sum of the zeroes 4
one of the zero is 2+√5==α
another zero is 2-√5==β because 2+√5+β=4
β=4-2+√5
β=2-√5
So here in order to get the equation we need substitute in general formula of quadratic equation
x²-(α+β)+αb
x²-(4)x+(2+√5.2-√5) {(a+b)(a-b)==a²-b²}
x²-4x+(4-5)
x²-4x+(-1)
x²-4x-1 is the answer