Question

form a quadratic polynomial whose zeroes are 3+root2 and 3-root2

Answer 1

Answer:

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Answer 2

Given roots :- (3+ √2) and (3-√2)

Sum of zeros = -b/a

=> 3+√2+3-√2 = -b/a

=> 6 = -b/a

Product of zeros = c/a

=> (3+√2)(3-√2) = c/1

=> 7 = c

Hence ,

b= -6

a = 1

c = 7

Polynomial = x² -6x +7