Form a three digit number using the digits 6,1 and 8. Find the sum of that number and the number formed by rearranging its digit in cycling order check whether the sum is divisible by the following numbers: a.111 and b. 37
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Answer:
give number378
to find Question
solution: the other two number obtained by arranging 378 in cyclic manners are783 and 837
Hence sum of the three number is
S=378+783+837=1998
when 1998 is divided by 111
=>1998/111 =18
Answer hence the quotient will be18
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