Question

form all possible 3 digit numbers from the numbers 1,2 and 3 using the digits only once: 2,1,3

Answer 1

The possible 3 digit numbers formed with 1,2 and 3 without repeating any numbers are many.

They are:

123.
132.
231.
213.
312.
321.

There are 6 numbers that can be formed out of the digits 1,2 and 3 without repeating the digits.

Answer 2

Concept Introduction: Permutations and combinations are the basic concept of Mathematics.

Given:

We have been Given: The numbers

$1 \: \: 2 \: and \: 3$

To Find:

We have to Find: Form all possible three digit numbers with this three digits, using only once.

Solution:

According to the problem, there are three digits given, therefore the total number of permutations that will be formed is

$3! = 6$

therefore the numbers are:

$123 \\ 132 \\ 231 \\ 213 \\ 312 \\ 321$

Final Answer: The all possible three digit numbers are

$123 \\ 132 \\ 231 \\ 213 \\ 312 \\ 321$

#SPJ2