Math, asked by yashsingh403, 5 hours ago

Form an equation for the following situation : The product of two consecutive natural numbers is 132.​

Answers

Answered by yogitaashu
0

Answer:

x \times x + 1 = 132

Step-by-step explanation:

x is a natural number.

value is

 \sqrt[3]{131}

Answered by kunalmathpal
0

Answer:

let no. be x,x+1

ATQ

x(x + 1) = 132 \\  {x}^{2}  + x = 132 \\  {x}^{2}  + x - 132

using quadratic equations

D=b2-4ax

 {1}^{2}  - 4 \times 1 \times  - 132 \\ 1 + 528 \\ 529

x =  - b \frac{ - }{ + }  \sqrt{d}  \div 2a

x =  \frac{ - 1 + 23}{2}  \\ 22 \div 2 = 11

 x =  \frac{ - 1 - 23}{2}  \\  - 24 \div 2 =  - 12

hence,

x = 11 \: or \: x =  - 12

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