Question

Form an equation for the following situation : The product of two consecutive natural numbers is 132.​

Answer 1

Answer:

$x \times x + 1 = 132$

Step-by-step explanation:

x is a natural number.

value is

$\sqrt[3]{131}$

Answer 2

Answer:

let no. be x,x+1

ATQ

$x(x + 1) = 132 \\ {x}^{2} + x = 132 \\ {x}^{2} + x - 132$

using quadratic equations

D=b2-4ax

${1}^{2} - 4 \times 1 \times - 132 \\ 1 + 528 \\ 529$

$x = - b \frac{ - }{ + } \sqrt{d} \div 2a$

$x = \frac{ - 1 + 23}{2} \\ 22 \div 2 = 11$

$x = \frac{ - 1 - 23}{2} \\ - 24 \div 2 = - 12$

hence,

$x = 11 \: or \: x = - 12$