form the equation whose roots are 2 times the roots of x3+7x+8=0
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Given equation is f(x) = x3 + 3x2 – 7x + 6 = 0 Required equation is f(√x) = 0 ⇒ x√x + 3x – 7√x + 6 = 0 ⇒ √x(x – 7) = – (3x + 6) Squaring on both sides, ⇒ x(x – 7)2 = (3x + 6)2 ⇒ x(x2 – 14x + 49) = 9x2 + 36 +36x ⇒ x3 – 14x2 + 49x – 9x2 – 36x – 36 = 0 i.e. x3 – 23x2 + 13x – 36 = 0Read more on Sarthaks.com - https://www.sarthaks.com/533694/form-the-polynomial-equation-whose-roots-are-the-squares-of-the-roots-of-x-3-3x-2-7x-6-0p
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