Form the quadratic equation and solve
The sum of two natural numbers and it's reciprocal is 10/3 .Find the no.s
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Let the number be x .
According to the question
x + 1/x = 10/3
(x2+1)/x=10/3
3x2 + 3 = 10x
3x2-10x + 3 = 0
3x2- 9x - x + 3 = o
3x(x - 3) -1(x - 3) = 0
x = 1/3 or x=3.
Hope it helps
^_^
According to the question
x + 1/x = 10/3
(x2+1)/x=10/3
3x2 + 3 = 10x
3x2-10x + 3 = 0
3x2- 9x - x + 3 = o
3x(x - 3) -1(x - 3) = 0
x = 1/3 or x=3.
Hope it helps
^_^
Anonymous:
Hope this helps you
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