Form the quadratic equation of a polynomial whose zeros are-1and5
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Answered by
3
let α=-1,β=5 then quadratic equation is
kx square -k(α+β)x+kαβ
kx square -k(-1+5)x+k(-1*5)
kx square -k(-4)x+k(-5)
so the equation is kx square +4kx-5k
so this is your answer
kx square -k(α+β)x+kαβ
kx square -k(-1+5)x+k(-1*5)
kx square -k(-4)x+k(-5)
so the equation is kx square +4kx-5k
so this is your answer
Answered by
3
Good evening
Here is the answer pf your question..................................................................
.......................................................................................................................... α = -1
β = 5
So, zeroes are
α+β = 5+(-1)
= 5-1
α+β = 4
αβ = 5×-1
αβ = -5
∴ Quadratic equation = x²-(α+β)x+αβ
= x²-(4)x+(-5)
= x²-4x-5 Ans.........
I think i helped you in this this question.
Good Night................................................................................................. :-)
Here is the answer pf your question..................................................................
.......................................................................................................................... α = -1
β = 5
So, zeroes are
α+β = 5+(-1)
= 5-1
α+β = 4
αβ = 5×-1
αβ = -5
∴ Quadratic equation = x²-(α+β)x+αβ
= x²-(4)x+(-5)
= x²-4x-5 Ans.........
I think i helped you in this this question.
Good Night................................................................................................. :-)
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