Question

form the quadratic equation whose roots are 2√3-5&-2√3-5​

Answer 1

Explanation:

ANSWER:

Polynomial is (x²+10x+13)

GIVEN:

α = 2√3-5

β = -2√3-5

TO FIND:

Quadratic equation.

SILUTION:

Quadratic polynomial

Here :

α = 2√3-5

β = -2√3-5

=> (α +β ) = 2√3-5+(-2√3-5)

=>(α +β) = (2√3-2√3)+(-5-5)

=>(α +β) = (-10)

=>αβ = (2√3-5)(-2√3-5)

=>αβ = (-5+2√3)(-5-2√3)

=>αβ = (-5)² -(2√3)²

=>αβ = 25 -12

=>αβ = 13

Now putting the values in eq(i)

P(x) = x²-(-10)x +13

p(x) = x²+10x+13

Polynomial is (x²+10x+13)