Question

form the quadratic equation whose roots are 3-root 7 and 3+root 7​

Answer 1

Step-by-step explanation:

(x-(3-√7))(x+(3+√7))

(x-3+√7)(x+3+√7)

(x+√7-3)(x+√7+3)

(x+√7)^2 - (3)^2

(x2+7+2√7x) - 9

x2+2√7x-2

Answer 2

Answer:

Therefore the polynomial is x2-6x+16

Step-by-step explanation:

Given two zeros as 3-root7 and 3+root7

take alpha=3-root7

take beta=3+root7

alpha + beta =3+root7+3-root7=6

alpha x beta =(3+root7) x (3-root7)

=3x3 +root7 x root7

=9+7=16

k[x2 -(alpha+beta)x + alpha x beta]

k[x2 - 6x + 16]

HOPE IT HELPS!!!!!!