Question

form the quadratic polynomial whose zeros are 4 and -6​

Answer 1

Step-by-step explanation:

$]\large{\boxed{\sf{\red{hope\:this\:helps\:you. }}}}$

Answer 2

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\sf\pink{A \: quadratic \: function \: is \: one \: of \: the form} \\ \\ \sf\red{f(x) = {ax}^{2} + bx + c \: where \: a, b, and c} \\ \\ \sf\pink{ are \: numbers \: with \: a not \: equal \: to \: 0 } \\ \\ \sf\red{here \: sum\: of \:the \:roots\:\alpha =4 \: and \: \beta = - 6 } \\ \\ \sf\red{product \:of\:the\:roots\:\alpha + \beta = 4 + ( - 6) } \\ \\ \sf\red{ = > 4 - 6 = - 2} \\ \\ \sf\red{\alpha \times \beta} \\ \\ \sf\pink{ = 4 \times ( - 6) = - 24}$

$\sf\red{ \alpha \: and \: \beta \: are \: the \: roots\: of \: the \: {ax}^{2} + bx + c } \\ \\ \sf\red{ answer = {x}^{2} +2x - 24 } \\ \\ \large\boxed{ \fcolorbox{green}{yellow}{hope \: it \: help \: you}}$