Question

Formal charge of P and H in ph3 respectively

pls answer it's really important​

Answer 1

To find:

Formal charge of P and H in PH3

Calculation:

General expression for formal charge is:

$\boxed{ \sf{FC = valence \: e - \bigg \{ \dfrac{1}{2} (bonding \: e) + lone \: pair \: e\bigg \}}}$

For phosphorus in PH3 (phosphene):

$\sf{FC = valence \: e - \bigg \{ \dfrac{1}{2} (bonding \: e) + lone \: pair \: e\bigg \}}$

$= > \sf{FC = 5 - \bigg \{ \dfrac{1}{2} (6) + 2\bigg \}}$

$= > \sf{FC = 5 - \bigg \{ 3 + 2\bigg \}}$

$= > \sf{FC = 5 - \bigg \{5\bigg \}}$

$= > \sf{FC = 0}$

For Hydrogen in PH3 (phosphene):

$\sf{FC = valence \: e - \bigg \{ \dfrac{1}{2} (bonding \: e) + lone \: pair \: e\bigg \}}$

$= > \sf{FC = 1- \bigg \{ \dfrac{1}{2} (2) + 0\bigg \}}$

$= > \sf{FC = 1- \bigg \{ 1 + 0\bigg \}}$

$= > \sf{FC = 1- \bigg \{ 1\bigg \}}$

$= > \sf{FC = 0}$

Hence , both Phosphorus and Hydrogen has zero formal charge in PH3.