Formation of 3.65g of HCl .What volume of H2 and Cl2 are required at NTP
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M° hcl= 36.5
moles of hcl = 0.1
cl2 +h2=2hcl
use stoichiometric ratios to get
0.05 moles of cl and h each
for volm 1 mole has 22.4llitre
0.05 mole will have 1.12litre
moles of hcl = 0.1
cl2 +h2=2hcl
use stoichiometric ratios to get
0.05 moles of cl and h each
for volm 1 mole has 22.4llitre
0.05 mole will have 1.12litre
rheabandari18:
Thank you so much
ur wlcm!
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