Question

formed.
A
13. In the given figure, ABCD is a rectangle in which AB = 26 cm
and AD = 45 cm. Also, BEC is a right triangle in which ZDEC
= 90° and BE = 10 cm. Find the area of the shaded portion.
B
С​

Answer 1

Answer:

see attachment

hope it helps you..

Answer 2

Answer:

Clearly, DC = AB = 26 cm.

Now, in right triangle DEC, we have:

DE = √DC – CE = √(26) – (10)

= √(26 +10)(26 - 10) cm = √36 x 16 cm

= (6 x 4) cm = 24 cm.

- Area of ∆DEC

$\frac{1}{2} \times DE × CE$

$( \frac{1}{2} \times 24 \times 10)cm {}^{2} = 120cm {}^{2}$

Area of rect. ABCD = (45 x 26) cm² = 1170 cm².

:. Area of the shaded region

= (area of rect. ABCD) - (area of ADEC)

= (1170 - 120) cm²= 1050 cm²

more to know.

• the measure of the surface enclosed by a plane figure is called area
• perimeter the perimeter of a plane figure is the length of its boundary