Question

FORMULA FOR (a+b+c)^3​

Answer 1

Answer:

HEYA MATE HERE'S YOUR REQUIRED FORMULA FOR (a+b+c)^3

=a^3+b^3^+c^3+3a^2b+3a^2c+3b^c+3b^2a+3c^2b+3c^2a+6abc

HOPE THIS HELPS ..☺️

Answer 2

a+b+c)3=[(a+b)+c]3=(a+b)3+3(a+b)2c+3(a+b)c2+c3

(a+b+c)3=(a3+3a2b+3ab2+b3)+3(a2+2ab+b2)c+3(a+b)c2+c3

(a+b+c)3=a3+b3+c3+3a2b+3a2c+3ab2+3b2c+3ac2+3bc2+6abc

(a+b+c)3=(a3+b3+c3)+(3a2b+3a2c+3abc)+(3ab2+3b2c+3abc)+(3ac2+3bc2+3abc)−3abc

(a+b+c)3=(a3+b3+c3)+3a(ab+ac+bc)+3b(ab+bc+ac)+3c(ac+bc+ab)−3abc

(a+b+c)3=(a3+b3+c3)+3(a+b+c)(ab+ac+bc)−3abc

(a+b+c)3=(a3+b3+c3)+3[(a+b+c)(ab+ac+bc)−abc]

Formula is (a - b)2 = a2 - 2ab+ b2 . 3.(a + b)3 = a3 + b3 + 3ab(a + b). 4. (a - b)3 = a3 - b3 - 3ab(a - b). 5.(a + b + c)2 = a2 + b2 + c2 +2ab+2bc +2ca. 6.(a + b + c)3 = a3 + b3 + c3+3a2b+3a2c + 3b2c +3b2a +3c2a +3c2a+6abc. 7.a2 - b2 = (a + b)(a – b ) .

Final formula = (a+b)(a-b)