formula for finding hypotanuse
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(H)1 = (P)² + (B)². ( where P = perpendicular and B is base.)
Anonymous:
1D fan
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Using Pythagoras theorum
a^2 +b^2=c^2
Here a is the base, b is the perpendicular and c is the hypotenuse
a^2 +b^2=c^2
Here a is the base, b is the perpendicular and c is the hypotenuse
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