Question

formula of (-a+b+c)²​

Answer 1

a²+b²+c²-2ab+2bc-2ca

Answer 2

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\blue{\:\: Given:-\:\:\:}}$

$\sf (-a+b+c){}^{2}$

$\sf\underline{\purple{\:\: Solution:-\:\:\:}}$

we know that

$\sf (a+b+c){}^{2}=a{}^{2}+b{}^{2}+c{}^{2}+2ab+2bc+ca\\ \\ \sf \:\:Now (-a+b+c){}^{2}\\ \\ \sf\:\:put\:the\: value\:in\:palce\:of\:that\\ \\ \sf\ (-a){}^{2}+(b){}^{2}+(c){}^{2}+2\times (-a)b+2bc+2c\times (-a)\\ \\ \sf\implies a{}^{2}+b{}^{2}+c{}^{2}-2ab+2bc-2ca$

$\boxed{\sf{\tt{\purple{a{}^{2}+b{}^{2}+c{}^{2}-2ab+2bc-2ca}}}}$