Question

formula of area of trapezium ​

Answer 1

Answer:-

Formula of Area of Trapezium ::-- (Required Answer)

$\boxed{\tt{ \frac{1}{2} \times Sum \: of \: || \: sides \times Distance \: between \: them }}$

_____________...

TheAssassin's BRAIN BOOSTER:-

Example : (Demo)

Question:

Find the area of the Trapezium when sum of the parallel side is 8 cm and height is 2 cm.

Answer:

Given:-

• Sum of || sides = 8 cm
• Distance between them = 2 cm

Hence, according to the formula:-

$\tt{\frac{1}{2} \times 8 \times 2 \ {cm}^{2}}$

(Equation formation)

$\tt{= \frac{1}{\cancel {2}} \times{\cancel{ 8}} \times 2 \ {cm}^{2}}$

(Cancelled 2 and 8 by taking common 2)

$\tt{= 4 \times 2 \ {cm}^{2}}$

(After cancellation)

$\tt{= 8 \ {cm}^{2}}$

(Area of the Trapezium)

_______...

Similar Questions that I've answered and can help you :-

https://brainly.in/question/14396941

Answer 2

$\huge\underline\red{\sf ToFind :-}$

★ Area of Trapezium ★

$\small\implies{\sf }$ $\huge{\sf {\frac{1}{2}}}$ x ( Sum of its parallel sides) x ( Distance between them)

★ Let's Find the area of given trapezium★ [ see attached figure ]

Given:

• AB = 14 cm , CD = 20 cm and EF = 12 cm

To Find:

• Area of Trapezium ABCD

Solution:

$\small\implies{\sf }$ $\huge{\sf {\frac{<strong>1</strong>}{<strong>2</strong>}}}$ x ( sum of || sides) x ( distance between them)

$\small\implies{\sf }$ $\huge{\sf {\frac{<strong>1</strong>}{<strong>2</strong>}}}$ x ( AB + DC ) x ( EF )

$\small\implies{\sf }$ $\huge{\sf {\frac{<strong>1</strong>}{<strong>2</strong>}}}$ x ( 14 + 20 ) x 12

$\small\implies{\sf }$ $\huge{\sf {\frac{<strong>1</strong>}{<strong>2</strong>}}}$ x 34 x 12

$\small\implies{\sf }$ 204 cm²

Hence, The area of Trapezium ABCD will be 204cm²